Question

$$24-8 { x }^{ 2 } =0$$

Answer

x=sqrt(3),-sqrt(3)

Solution


Subtract \(24\) from both sides.
\[-8{x}^{2}=-24\]
Divide both sides by \(-8\).
\[{x}^{2}=\frac{-24}{-8}\]
Two negatives make a positive.
\[{x}^{2}=\frac{24}{8}\]
Simplify  \(\frac{24}{8}\)  to  \(3\).
\[{x}^{2}=3\]
Take the square root of both sides.
\[x=\pm \sqrt{3}\]

Decimal Form: ±1.732051