How to solve 240-{40-3(12-9)}

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 240-{40-3(12-9)} | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$240- \{ 40-3(12-9) \}$$

Evaluate

$209$

Solution Steps

Subtract $9$ from $12$ to get $3$.

$$240-\left(40-3\times 3\right)$$

Multiply $3$ and $3$ to get $9$.

$$240-\left(40-9\right)$$

Subtract $9$ from $40$ to get $31$.

$$240-31$$

Subtract $31$ from $240$ to get $209$.

$$209$$

Show Solution

Factor

$11\times 19$

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