How to solve 2411 by 1345

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2411 by 1345 | Equatix

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Question

$$2411 1345$$

Evaluate

$3242795$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times999}2411\\\underline{\times\phantom{999}1345}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 2411 with 5. Write the result 12055 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}2411\\\underline{\times\phantom{999}1345}\\\phantom{\times99}12055\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 2411 with 4. Write the result 9644 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}2411\\\underline{\times\phantom{999}1345}\\\phantom{\times99}12055\\\phantom{\times99}9644\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 2411 with 3. Write the result 7233 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}2411\\\underline{\times\phantom{999}1345}\\\phantom{\times99}12055\\\phantom{\times99}9644\phantom{9}\\\phantom{\times9}7233\phantom{99}\\\end{array}$$

Now multiply the first number with the $4^{th}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 2411 with 1. Write the result 2411 at the end leaving 3 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}2411\\\underline{\times\phantom{999}1345}\\\phantom{\times99}12055\\\phantom{\times99}9644\phantom{9}\\\phantom{\times9}7233\phantom{99}\\\underline{\phantom{\times}2411\phantom{999}}\\\end{array}$$

Now add the intermediate results to get final answer.

Show Solution

Factor

$5\times 269\times 2411$