How to solve 243*427(

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 243*427( | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Question

$$243\times427($$

Evaluate

$103761$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times999}243\\\underline{\times\phantom{999}427}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 243 with 7. Write the result 1701 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}243\\\underline{\times\phantom{999}427}\\\phantom{\times99}1701\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 243 with 2. Write the result 486 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}243\\\underline{\times\phantom{999}427}\\\phantom{\times99}1701\\\phantom{\times99}486\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 243 with 4. Write the result 972 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}243\\\underline{\times\phantom{999}427}\\\phantom{\times99}1701\\\phantom{\times99}486\phantom{9}\\\underline{\phantom{\times9}972\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times999}243\\\underline{\times\phantom{999}427}\\\phantom{\times99}1701\\\phantom{\times99}486\phantom{9}\\\underline{\phantom{\times9}972\phantom{99}}\\\phantom{\times}103761\end{array}$$

Show Solution

Factor

$3^{5}\times 7\times 61$