1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2445/15 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Question

$$2445\div15$$

Evaluate

$163$

Steps For Long Division Method

Use the $1^{st}$ digit $2$ from dividend $2445$

$$\begin{array}{l}\phantom{15)}\phantom{1}\\15\overline{)2445}\\\end{array}$$

Since $2$ is less than $15$, use the next digit $4$ from dividend $2445$ and add $0$ to the quotient

$$\begin{array}{l}\phantom{15)}0\phantom{2}\\15\overline{)2445}\\\end{array}$$

Use the $2^{nd}$ digit $4$ from dividend $2445$

$$\begin{array}{l}\phantom{15)}0\phantom{3}\\15\overline{)2445}\\\end{array}$$

Find closest multiple of $15$ to $24$. We see that $1 \times 15 = 15$ is the nearest. Now subtract $15$ from $24$ to get reminder $9$. Add $1$ to quotient.

$$\begin{array}{l}\phantom{15)}01\phantom{4}\\15\overline{)2445}\\\phantom{15)}\underline{\phantom{}15\phantom{99}}\\\phantom{15)9}9\\\end{array}$$

Use the $3^{rd}$ digit $4$ from dividend $2445$

$$\begin{array}{l}\phantom{15)}01\phantom{5}\\15\overline{)2445}\\\phantom{15)}\underline{\phantom{}15\phantom{99}}\\\phantom{15)9}94\\\end{array}$$

Find closest multiple of $15$ to $94$. We see that $6 \times 15 = 90$ is the nearest. Now subtract $90$ from $94$ to get reminder $4$. Add $6$ to quotient.

$$\begin{array}{l}\phantom{15)}016\phantom{6}\\15\overline{)2445}\\\phantom{15)}\underline{\phantom{}15\phantom{99}}\\\phantom{15)9}94\\\phantom{15)}\underline{\phantom{9}90\phantom{9}}\\\phantom{15)99}4\\\end{array}$$

Use the $4^{th}$ digit $5$ from dividend $2445$

$$\begin{array}{l}\phantom{15)}016\phantom{7}\\15\overline{)2445}\\\phantom{15)}\underline{\phantom{}15\phantom{99}}\\\phantom{15)9}94\\\phantom{15)}\underline{\phantom{9}90\phantom{9}}\\\phantom{15)99}45\\\end{array}$$

Find closest multiple of $15$ to $45$. We see that $3 \times 15 = 45$ is the nearest. Now subtract $45$ from $45$ to get reminder $0$. Add $3$ to quotient.

$$\begin{array}{l}\phantom{15)}0163\phantom{8}\\15\overline{)2445}\\\phantom{15)}\underline{\phantom{}15\phantom{99}}\\\phantom{15)9}94\\\phantom{15)}\underline{\phantom{9}90\phantom{9}}\\\phantom{15)99}45\\\phantom{15)}\underline{\phantom{99}45\phantom{}}\\\phantom{15)9999}0\\\end{array}$$

Since $0$ is less than $15$, stop the division. The reminder is $0$. The topmost line $0163$ is the quotient. Remove all zeros at the start of the quotient to get the actual quotient $163$.

$$\text{Quotient: }163$$ $$\text{Reminder: }0$$

Show Solution

Factor