Solve 24x-3[5x-8(2x-4)+1] | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$24x-3[5x-8(2x-4)+1]$$

Evaluate

$57x-99$

Solution Steps

Use the distributive property to multiply $-8$ by $2x-4$.

$$24x-3\left(5x-16x+32+1\right)$$

Combine $5x$ and $-16x$ to get $-11x$.

$$24x-3\left(-11x+32+1\right)$$

Add $32$ and $1$ to get $33$.

$$24x-3\left(-11x+33\right)$$

Use the distributive property to multiply $-3$ by $-11x+33$.

$$24x+33x-99$$

Combine $24x$ and $33x$ to get $57x$.

$$57x-99$$

Expand

$57x-99$

Solution Steps

Use the distributive property to multiply $-8$ by $2x-4$.

$$24x-3\left(5x-16x+32+1\right)$$

Combine $5x$ and $-16x$ to get $-11x$.

$$24x-3\left(-11x+32+1\right)$$

Add $32$ and $1$ to get $33$.

$$24x-3\left(-11x+33\right)$$

Use the distributive property to multiply $-3$ by $-11x+33$.

$$24x+33x-99$$

Combine $24x$ and $33x$ to get $57x$.

$$57x-99$$