$$25 { x }^{ 2 } -40 { x }^{ 2 } +16 { x }^{ 2 }$$
$x^{2}$
$$-15x^{2}+16x^{2}$$
$$x^{2}$$
Show Solution
Hide Solution
$2x$
$$\frac{\mathrm{d}}{\mathrm{d}x}(-15x^{2}+16x^{2})$$
$$\frac{\mathrm{d}}{\mathrm{d}x}(x^{2})$$
$$2x^{2-1}$$
$$2x^{1}$$
$$2x$$