Solve 25 - C * 12 - [10 - [7 - 5 - 3]] | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$25-C12-[10-[7-5-3]]$$

Evaluate

$14-C_{12}$

Solution Steps

Subtract $5$ from $7$ to get $2$.

$$25-C_{12}-\left(10-\left(2-3\right)\right)$$

Subtract $3$ from $2$ to get $-1$.

$$25-C_{12}-\left(10-\left(-1\right)\right)$$

The opposite of $-1$ is $1$.

$$25-C_{12}-\left(10+1\right)$$

Add $10$ and $1$ to get $11$.

$$25-C_{12}-11$$

Subtract $11$ from $25$ to get $14$.

$$14-C_{12}$$

Expand

$14-C_{12}$

Solution Steps

Subtract $5$ from $7$ to get $2$.

$$25-C_{12}-\left(10-\left(2-3\right)\right)$$

Subtract $3$ from $2$ to get $-1$.

$$25-C_{12}-\left(10-\left(-1\right)\right)$$

The opposite of $-1$ is $1$.

$$25-C_{12}-\left(10+1\right)$$

Add $10$ and $1$ to get $11$.

$$25-C_{12}-11$$

Subtract $11$ from $25$ to get $14$.

$$14-C_{12}$$