How to solve 25-(8a-3)^(2)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 25-(8a-3)^(2) | Equatix

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Question

$$25- { \left(8a-3 \right) }^{ 2 }$$

Evaluate

$16+48a-64a^{2}$

Solution Steps

Use binomial theorem $\left(p-q\right)^{2}=p^{2}-2pq+q^{2}$ to expand $\left(8a-3\right)^{2}$.

$$25-\left(64a^{2}-48a+9\right)$$

To find the opposite of $64a^{2}-48a+9$, find the opposite of each term.

$$25-64a^{2}+48a-9$$

Subtract $9$ from $25$ to get $16$.

$$16-64a^{2}+48a$$

Show Solution

Expand

$16+48a-64a^{2}$

Solution Steps

Use binomial theorem $\left(p-q\right)^{2}=p^{2}-2pq+q^{2}$ to expand $\left(8a-3\right)^{2}$.

$$25-\left(64a^{2}-48a+9\right)$$

To find the opposite of $64a^{2}-48a+9$, find the opposite of each term.

$$25-64a^{2}+48a-9$$

Subtract $9$ from $25$ to get $16$.

$$16-64a^{2}+48a$$

Show Solution

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Example

Question

Evaluate

Solution Steps

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Solution Steps