Solve [25+18\ 10-3(48/12)+4\ \ | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$[25+18\{10-3(48\div12)+4\}\}$$

Evaluate

$61$

Solution Steps

Divide $48$ by $12$ to get $4$.

$$25+18\left(10-3\times 4+4\right)$$

Multiply $3$ and $4$ to get $12$.

$$25+18\left(10-12+4\right)$$

Subtract $12$ from $10$ to get $-2$.

$$25+18\left(-2+4\right)$$

Add $-2$ and $4$ to get $2$.

$$25+18\times 2$$

Multiply $18$ and $2$ to get $36$.

$$25+36$$

Add $25$ and $36$ to get $61$.

$$61$$

Factor

$61$