$$256 { b }^{ 2 } { x }^{ 2 } -16$$
$16\left(4bx-1\right)\left(4bx+1\right)$
$$16\left(16b^{2}x^{2}-1\right)$$
$$\left(4bx-1\right)\left(4bx+1\right)$$
$$16\left(4bx-1\right)\left(4bx+1\right)$$
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$256\left(bx\right)^{2}-16$
