$$256/(-15-1)-(-6 \times 15+13 \times 3)/3$$
$1$
$$\frac{256}{-16}-\frac{-6\times 15+13\times 3}{3}$$
$$-16-\frac{-6\times 15+13\times 3}{3}$$
$$-16-\frac{-90+39}{3}$$
$$-16-\frac{-51}{3}$$
$$-16-\left(-17\right)$$
$$-16+17$$
$$1$$
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