How to solve 2635 by 435

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2635 by 435 | Equatix

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Question

$$2635 435$$

Evaluate

$1146225$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times999}2635\\\underline{\times\phantom{9999}435}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 2635 with 5. Write the result 13175 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}2635\\\underline{\times\phantom{9999}435}\\\phantom{\times99}13175\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 2635 with 3. Write the result 7905 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}2635\\\underline{\times\phantom{9999}435}\\\phantom{\times99}13175\\\phantom{\times99}7905\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 2635 with 4. Write the result 10540 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}2635\\\underline{\times\phantom{9999}435}\\\phantom{\times99}13175\\\phantom{\times99}7905\phantom{9}\\\underline{\phantom{\times}10540\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

Show Solution

Factor

$3\times 5^{2}\times 17\times 29\times 31$