How to solve 26781 imes93

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 26781\times93 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Question

$$26781 \times 93$$

Evaluate

$2490633$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times99}26781\\\underline{\times\phantom{99999}93}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 26781 with 3. Write the result 80343 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}26781\\\underline{\times\phantom{99999}93}\\\phantom{\times99}80343\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 26781 with 9. Write the result 241029 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}26781\\\underline{\times\phantom{99999}93}\\\phantom{\times99}80343\\\underline{\phantom{\times}241029\phantom{9}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times99}26781\\\underline{\times\phantom{99999}93}\\\phantom{\times99}80343\\\underline{\phantom{\times}241029\phantom{9}}\\\phantom{\times}2490633\end{array}$$

Show Solution

Factor

$3^{2}\times 31\times 79\times 113$