Solve 27-[38-\ 46-(15-13-12)3] | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Question

$$27-[38-\{46-(15-13-12)3]$$

Evaluate

$4b-1$

Solution Steps

Subtract $13$ from $15$ to get $2$.

$$27-\left(38-\left(4b-\left(2-12\right)\right)\right)$$

Subtract $12$ from $2$ to get $-10$.

$$27-\left(38-\left(4b-\left(-10\right)\right)\right)$$

The opposite of $-10$ is $10$.

$$27-\left(38-\left(4b+10\right)\right)$$

To find the opposite of $4b+10$, find the opposite of each term.

$$27-\left(38-4b-10\right)$$

Subtract $10$ from $38$ to get $28$.

$$27-\left(28-4b\right)$$

To find the opposite of $28-4b$, find the opposite of each term.

$$27-28-\left(-4b\right)$$

The opposite of $-4b$ is $4b$.

$$27-28+4b$$

Subtract $28$ from $27$ to get $-1$.

$$-1+4b$$

Show Solution

Expand

$4b-1$

Solution Steps

Subtract $13$ from $15$ to get $2$.

$$27-\left(38-\left(4b-\left(2-12\right)\right)\right)$$

Subtract $12$ from $2$ to get $-10$.

$$27-\left(38-\left(4b-\left(-10\right)\right)\right)$$

The opposite of $-10$ is $10$.

$$27-\left(38-\left(4b+10\right)\right)$$

To find the opposite of $4b+10$, find the opposite of each term.

$$27-\left(38-4b-10\right)$$

Subtract $10$ from $38$ to get $28$.

$$27-\left(28-4b\right)$$

To find the opposite of $28-4b$, find the opposite of each term.

$$27-28-\left(-4b\right)$$

The opposite of $-4b$ is $4b$.

$$27-28+4b$$

Subtract $28$ from $27$ to get $-1$.

$$-1+4b$$

Show Solution

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Example

Question

Evaluate

Solution Steps

Expand

Solution Steps