$$27 p ^ { 3 } - \frac { 1 } { 216 } - \frac { 9 } { 2 } p ^ { 2 } + \frac { 1 } { 4 } p$$
$\frac{\left(18p-1\right)^{3}}{216}$
$$\frac{5832p^{3}-1-972p^{2}+54p}{216}$$
$$\left(18p-1\right)^{3}$$
$$\frac{\left(18p-1\right)^{3}}{216}$$
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