$$28- \{ 25-[9 \div (17+3 \times 2-20)] \}$$
$6$
$$28-\left(25-\frac{9}{17+6-20}\right)$$
$$28-\left(25-\frac{9}{23-20}\right)$$
$$28-\left(25-\frac{9}{3}\right)$$
$$28-\left(25-3\right)$$
$$28-22$$
$$6$$
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$2\times 3$