How to solve 284 imes235

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 284\times235 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Question

$$284 \times 235$$

Evaluate

$66740$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times99}284\\\underline{\times\phantom{99}235}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 284 with 5. Write the result 1420 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}284\\\underline{\times\phantom{99}235}\\\phantom{\times9}1420\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 284 with 3. Write the result 852 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}284\\\underline{\times\phantom{99}235}\\\phantom{\times9}1420\\\phantom{\times9}852\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 284 with 2. Write the result 568 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}284\\\underline{\times\phantom{99}235}\\\phantom{\times9}1420\\\phantom{\times9}852\phantom{9}\\\underline{\phantom{\times}568\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times99}284\\\underline{\times\phantom{99}235}\\\phantom{\times9}1420\\\phantom{\times9}852\phantom{9}\\\underline{\phantom{\times}568\phantom{99}}\\\phantom{\times}66740\end{array}$$

Show Solution

Factor

$2^{2}\times 5\times 47\times 71$