How to solve 28490x3079

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 28490x3079 | Equatix

Question

$$28490x3079$$

Evaluate

$28490x_{3079}$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times999}28490\\\underline{\times\phantom{9999}3079}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 28490 with 9. Write the result 256410 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}28490\\\underline{\times\phantom{9999}3079}\\\phantom{\times99}256410\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 28490 with 7. Write the result 199430 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}28490\\\underline{\times\phantom{9999}3079}\\\phantom{\times99}256410\\\phantom{\times9}199430\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 28490 with 0. Write the result 0 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}28490\\\underline{\times\phantom{9999}3079}\\\phantom{\times99}256410\\\phantom{\times9}199430\phantom{9}\\\phantom{\times999999}0\phantom{99}\\\end{array}$$

Now multiply the first number with the $4^{th}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 28490 with 3. Write the result 85470 at the end leaving 3 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}28490\\\underline{\times\phantom{9999}3079}\\\phantom{\times99}256410\\\phantom{\times9}199430\phantom{9}\\\phantom{\times999999}0\phantom{99}\\\underline{\phantom{\times}85470\phantom{999}}\\\end{array}$$

Now add the intermediate results to get final answer.

Show Solution

Differentiate w.r.t. x_3079

$28490$

Steps Using Definition of a Derivative

The derivative of $ax^{n}$ is $nax^{n-1}$.

$$28490x_{3079}^{1-1}$$

Subtract $1$ from $1$.

$$28490x_{3079}^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$28490\times 1$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$28490$$

Show Solution

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Steps For Long Multiplication

Differentiate w.r.t. x_3079

Steps Using Definition of a Derivative