Solve 88 * 35/72 + (1.0625 - 5/12) * 16 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$2.88\times\frac{35}{72}+(1.0625-\frac{5}{12})\times16$$

Evaluate

$\frac{176}{15}\approx 11.733333333$

Solution Steps

Convert decimal number $2.88$ to fraction $\frac{288}{100}$. Reduce the fraction $\frac{288}{100}$ to lowest terms by extracting and canceling out $4$.

$$\frac{72}{25}\times \frac{35}{72}+\left(1.0625-\frac{5}{12}\right)\times 16$$

Multiply $\frac{72}{25}$ times $\frac{35}{72}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{72\times 35}{25\times 72}+\left(1.0625-\frac{5}{12}\right)\times 16$$

Cancel out $72$ in both numerator and denominator.

$$\frac{35}{25}+\left(1.0625-\frac{5}{12}\right)\times 16$$

Reduce the fraction $\frac{35}{25}$ to lowest terms by extracting and canceling out $5$.

$$\frac{7}{5}+\left(1.0625-\frac{5}{12}\right)\times 16$$

Convert decimal number $1.0625$ to fraction $\frac{10625}{10000}$. Reduce the fraction $\frac{10625}{10000}$ to lowest terms by extracting and canceling out $625$.

$$\frac{7}{5}+\left(\frac{17}{16}-\frac{5}{12}\right)\times 16$$

Least common multiple of $16$ and $12$ is $48$. Convert $\frac{17}{16}$ and $\frac{5}{12}$ to fractions with denominator $48$.

$$\frac{7}{5}+\left(\frac{51}{48}-\frac{20}{48}\right)\times 16$$

Since $\frac{51}{48}$ and $\frac{20}{48}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{7}{5}+\frac{51-20}{48}\times 16$$

Subtract $20$ from $51$ to get $31$.

$$\frac{7}{5}+\frac{31}{48}\times 16$$

Express $\frac{31}{48}\times 16$ as a single fraction.

$$\frac{7}{5}+\frac{31\times 16}{48}$$

Multiply $31$ and $16$ to get $496$.

$$\frac{7}{5}+\frac{496}{48}$$

Reduce the fraction $\frac{496}{48}$ to lowest terms by extracting and canceling out $16$.

$$\frac{7}{5}+\frac{31}{3}$$

Least common multiple of $5$ and $3$ is $15$. Convert $\frac{7}{5}$ and $\frac{31}{3}$ to fractions with denominator $15$.

$$\frac{21}{15}+\frac{155}{15}$$

Since $\frac{21}{15}$ and $\frac{155}{15}$ have the same denominator, add them by adding their numerators.

$$\frac{21+155}{15}$$

Add $21$ and $155$ to get $176$.

$$\frac{176}{15}$$

Factor

$\frac{11 \cdot 2 ^ {4}}{3 \cdot 5} = 11\frac{11}{15} = 11.733333333333333$