$$28x+4=3(x10)+7$$
$x=\frac{3\left(x_{10}+1\right)}{28}$
$$28x=3x_{10}+7-4$$
$$28x=3x_{10}+3$$
$$\frac{28x}{28}=\frac{3x_{10}+3}{28}$$
$$x=\frac{3x_{10}+3}{28}$$
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$x_{10}=\frac{28x}{3}-1$
$$3x_{10}+7=28x+4$$
$$3x_{10}=28x+4-7$$
$$3x_{10}=28x-3$$
$$\frac{3x_{10}}{3}=\frac{28x-3}{3}$$
$$x_{10}=\frac{28x-3}{3}$$
$$x_{10}=\frac{28x}{3}-1$$
