How to solve 293 imes50

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 293\times50 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Question

$$293 \times 50$$

Evaluate

$14650$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times99}293\\\underline{\times\phantom{999}50}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 293 with 0. Write the result 0 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}293\\\underline{\times\phantom{999}50}\\\phantom{\times99999}0\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 293 with 5. Write the result 1465 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}293\\\underline{\times\phantom{999}50}\\\phantom{\times99999}0\\\underline{\phantom{\times}1465\phantom{9}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times99}293\\\underline{\times\phantom{999}50}\\\phantom{\times99999}0\\\underline{\phantom{\times}1465\phantom{9}}\\\phantom{\times}14650\end{array}$$

Show Solution

Factor

$2\times 5^{2}\times 293$