$$2a(a-1)+3b(a-1)-(a-1)$$
$\left(a-1\right)\left(2a+3b-1\right)$
$$2a^{2}-2a+3b\left(a-1\right)-\left(a-1\right)$$
$$2a^{2}-2a+3ba-3b-\left(a-1\right)$$
$$2a^{2}-2a+3ba-3b-a-\left(-1\right)$$
$$2a^{2}-2a+3ba-3b-a+1$$
$$2a^{2}-3a+3ba-3b+1$$
Show Solution
Hide Solution
$2a^{2}+3ab-3a-3b+1$