$$2C \times 9C$$
$18C^{2}$
$$2C^{2}\times 9$$
$$18C^{2}$$
Show Solution
Hide Solution
$36C$
$$\frac{\mathrm{d}}{\mathrm{d}C}(2C^{2}\times 9)$$
$$\frac{\mathrm{d}}{\mathrm{d}C}(18C^{2})$$
$$2\times 18C^{2-1}$$
$$36C^{2-1}$$
$$36C^{1}$$
$$36C$$
