How to solve 2k ^ 2 + 5 =

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2k ^ 2 + 5 = | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Question

$$2k^{2}+5=$$

Differentiate w.r.t. k

$4k$

Steps Using Derivative Rule for Sum

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$2\times 2k^{2-1}$$

Multiply $2$ times $2$.

$$4k^{2-1}$$

Subtract $1$ from $2$.

$$4k^{1}$$

For any term $t$, $t^{1}=t$.

$$4k$$

Show Solution

Evaluate

$2k^{2}+5$