$$2P=P(1+0.025)N$$
$\left\{\begin{matrix}\\N=\frac{80}{41}\approx 1.951219512\text{, }&\text{unconditionally}\\N\in \mathrm{R}\text{, }&P=0\end{matrix}\right.$
$\left\{\begin{matrix}\\P=0\text{, }&\text{unconditionally}\\P\in \mathrm{R}\text{, }&N=\frac{80}{41}\end{matrix}\right.$
