$$2p+ \frac{ 3 }{ 4 } q-7p+ \frac{ 3 }{ 2 } q$$
$\frac{9q}{4}-5p$
$$-5p+\frac{3}{4}q+\frac{3}{2}q$$
$$-5p+\frac{9}{4}q$$
Show Solution
Hide Solution
$\frac{9q-20p}{4}$
$$\frac{8p+3q-28p+6q}{4}$$
$$-20p+9q$$
$$\frac{-20p+9q}{4}$$