Break down the problem into these 2 equations.
Solve the 1st equation: \(2x-2y-2=0\).
Solve the 2nd equation: \(2x-2y-2=4x-4y-5\).
Subtract \(2x\) from both sides.
\[-2y-2=4x-4y-5-2x\]
Simplify \(4x-4y-5-2x\) to \(2x-4y-5\).
\[-2y-2=2x-4y-5\]
Add \(4y\) to both sides.
\[-2y-2+4y=2x-5\]
Simplify \(-2y-2+4y\) to \(2y-2\).
\[2y-2=2x-5\]
Add \(5\) to both sides.
\[2y-2+5=2x\]
Simplify \(2y-2+5\) to \(2y+3\).
\[2y+3=2x\]
Divide both sides by \(2\).
\[\frac{2y+3}{2}=x\]
Switch sides.
\[x=\frac{2y+3}{2}\]
Collect all solutions.
