How to solve 2x-3(15-3/5)=-9

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2x-3(15-3/5)=-9 | Equatix

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Question

$$2x-3(15-3/5)=-9$$

Solve for x

$x = \frac{171}{10} = 17\frac{1}{10} = 17.1$

Steps for Solving Linear Equation

Convert $15$ to fraction $\frac{75}{5}$.

$$2x-3\left(\frac{75}{5}-\frac{3}{5}\right)=-9$$

Since $\frac{75}{5}$ and $\frac{3}{5}$ have the same denominator, subtract them by subtracting their numerators.

$$2x-3\times \frac{75-3}{5}=-9$$

Subtract $3$ from $75$ to get $72$.

$$2x-3\times \frac{72}{5}=-9$$

Express $3\times \frac{72}{5}$ as a single fraction.

$$2x-\frac{3\times 72}{5}=-9$$

Multiply $3$ and $72$ to get $216$.

$$2x-\frac{216}{5}=-9$$

Add $\frac{216}{5}$ to both sides.

$$2x=-9+\frac{216}{5}$$

Convert $-9$ to fraction $-\frac{45}{5}$.

$$2x=-\frac{45}{5}+\frac{216}{5}$$

Since $-\frac{45}{5}$ and $\frac{216}{5}$ have the same denominator, add them by adding their numerators.

$$2x=\frac{-45+216}{5}$$

Add $-45$ and $216$ to get $171$.

$$2x=\frac{171}{5}$$

Divide both sides by $2$.

$$x=\frac{\frac{171}{5}}{2}$$

Express $\frac{\frac{171}{5}}{2}$ as a single fraction.

$$x=\frac{171}{5\times 2}$$

Multiply $5$ and $2$ to get $10$.

$$x=\frac{171}{10}$$

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