How to solve 2x-7/x-3

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2x-7/x-3 | Equatix

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$$2x-7/x-3$$

$2x-3-\frac{7}{x}$

To add or subtract expressions, expand them to make their denominators the same. Multiply $2x-3$ times $\frac{x}{x}$.

$$\frac{\left(2x-3\right)x}{x}-\frac{7}{x}$$

Since $\frac{\left(2x-3\right)x}{x}$ and $\frac{7}{x}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{\left(2x-3\right)x-7}{x}$$

Do the multiplications in $\left(2x-3\right)x-7$.

$$\frac{2x^{2}-3x-7}{x}$$

$\frac{2\left(x-\frac{3-\sqrt{65}}{4}\right)\left(x-\frac{\sqrt{65}+3}{4}\right)}{x}$