$$2x-y+3=0$$
$x=\frac{y-3}{2}$
$$2x+3=y$$
$$2x=y-3$$
$$\frac{2x}{2}=\frac{y-3}{2}$$
$$x=\frac{y-3}{2}$$
Show Solution
Hide Solution
$y=2x+3$
$$-y+3=-2x$$
$$-y=-2x-3$$
$$\frac{-y}{-1}=\frac{-2x-3}{-1}$$
$$y=\frac{-2x-3}{-1}$$
$$y=2x+3$$
