How to solve 2x+2 < 8-x

Q: How to solve 2x+2 < 8-x

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2x+2 < 8-x | Equatix

Integers & Absolute Values

Factors & Multiples

Prime Factorization

Basic Equations & Inequalities

Coordinate Plane & Graphing

Linear Equations & Inequalities

Quadratic Equations

Polynomials & Factoring

Functions & Graphs

Systems of Equations

Trigonometric Functions

Trigonometric Identities & Equations

Right Triangle Trigonometry

Unit Circle

Graphing Trigonometric Functions

Limits & Continuity

Derivatives & Applications

Integrals & Applications

Series & Sequences

Multivariable Calculus

Functions & Graphs

Polynomial & Rational Functions

Exponential & Logarithmic Functions

Conic Sections

Sequences & Series

Descriptive Statistics

Eigenvalues & Eigenvectors

Linear Transformations

Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$2x+2 < 8-x$$

Solve for x

$x<2$

Solution Steps

Add $x$ to both sides.

$$2x+2+x<8$$

Combine $2x$ and $x$ to get $3x$.

$$3x+2<8$$

Subtract $2$ from both sides.

$$3x<8-2$$

Subtract $2$ from $8$ to get $6$.

$$3x<6$$

Divide both sides by $3$. Since $3$ is positive, the inequality direction remains the same.

$$x<\frac{6}{3}$$

Divide $6$ by $3$ to get $2$.

$$x<2$$

Show Solution

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Example

Question

Solve for x

Solution Steps