How to solve 2x+3 > 9

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2x+3 > 9 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$2x+3 > 9$$

Solve for x

$x>3$

Solution Steps

Subtract $3$ from both sides.

$$2x>9-3$$

Subtract $3$ from $9$ to get $6$.

$$2x>6$$

Divide both sides by $2$. Since $2$ is positive, the inequality direction remains the same.

$$x>\frac{6}{2}$$

Divide $6$ by $2$ to get $3$.

$$x>3$$

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Solve for x

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