How to solve 2x+3(1-2x) < x+8

Q: How to solve 2x+3(1-2x) < x+8

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2x+3(1-2x) < x+8 | Equatix

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3(r+2s)=2t-4

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3(r+2s)=2t-4

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Question

$$2x+3(1-2x) < x+8$$

Solve for x

$x>-1$

Solution Steps

Use the distributive property to multiply $3$ by $1-2x$.

$$2x+3-6x<x+8$$

Combine $2x$ and $-6x$ to get $-4x$.

$$-4x+3<x+8$$

Subtract $x$ from both sides.

$$-4x+3-x<8$$

Combine $-4x$ and $-x$ to get $-5x$.

$$-5x+3<8$$

Subtract $3$ from both sides.

$$-5x<8-3$$

Subtract $3$ from $8$ to get $5$.

$$-5x<5$$

Divide both sides by $-5$. Since $-5$ is negative, the inequality direction is changed.

$$x>\frac{5}{-5}$$

Divide $5$ by $-5$ to get $-1$.

$$x>-1$$

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Solve for x

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