$$2x+3y-5=0$$
$x=\frac{5-3y}{2}$
$$2x-5=-3y$$
$$2x=-3y+5$$
$$2x=5-3y$$
$$\frac{2x}{2}=\frac{5-3y}{2}$$
$$x=\frac{5-3y}{2}$$
Show Solution
Hide Solution
$y=\frac{5-2x}{3}$
$$3y-5=-2x$$
$$3y=-2x+5$$
$$3y=5-2x$$
$$\frac{3y}{3}=\frac{5-2x}{3}$$
$$y=\frac{5-2x}{3}$$