Question

$$2X+ { x }^{ 2 } -8=0,2,-4$$

Solve for x (complex solution)

$x=-\sqrt{8-2X}$
$x=\sqrt{8-2X}\text{, }a=2$

Solve for x

$x=\sqrt{8-2X}$
$x=-\sqrt{8-2X}\text{, }X\leq 4\text{ and }a=2$