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Example
3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b
Question
$$2x+ \frac{ 3 }{ x } =5 \frac{ 1 }{ 2 }$$
Answer
x=(5+sqrt(71)*IM)/8,(5-sqrt(71)*IM)/8
Solution
Simplify \(5\times \frac{1}{2}\) to \(\frac{5}{2}\).
\[2x+\frac{3}{x}=\frac{5}{2}\]
Multiply both sides by \(2x\).
\[4{x}^{2}+6=5x\]
Move all terms to one side.
\[4{x}^{2}+6-5x=0\]
Use the Quadratic Formula.
In general, given \(a{x}^{2}+bx+c=0\), there exists two solutions where:
\[x=\frac{-b+\sqrt{{b}^{2}-4ac}}{2a},\frac{-b-\sqrt{{b}^{2}-4ac}}{2a}\]
In this case, \(a=4\), \(b=-5\) and \(c=6\).
\[{x}^{}=\frac{5+\sqrt{{(-5)}^{2}-4\times 4\times 6}}{2\times 4},\frac{5-\sqrt{{(-5)}^{2}-4\times 4\times 6}}{2\times 4}\]
Simplify.
\[x=\frac{5+\sqrt{71}\imath }{8},\frac{5-\sqrt{71}\imath }{8}\]
\[x=\frac{5+\sqrt{71}\imath }{8},\frac{5-\sqrt{71}\imath }{8}\]
x=(5+sqrt(71)*IM)/8,(5-sqrt(71)*IM)/8
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