How to solve 2x ^ 2 = 56

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2x ^ 2 = 56 | Equatix

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Question

$$2x^{2}=56$$

Solve for x

$x=2\sqrt{7}\approx 5.291502622$
$x=-2\sqrt{7}\approx -5.291502622$

Steps by Finding Square Root

Steps Using the Quadratic Formula

Steps by Finding Square Root

Divide both sides by $2$.

$$x^{2}=\frac{56}{2}$$

Divide $56$ by $2$ to get $28$.

$$x^{2}=28$$

Take the square root of both sides of the equation.

$$x=2\sqrt{7}$$ $$x=-2\sqrt{7}$$

Steps Using the Quadratic Formula

Divide both sides by $2$.

$$x^{2}=\frac{56}{2}$$

Divide $56$ by $2$ to get $28$.

$$x^{2}=28$$

Subtract $28$ from both sides.

$$x^{2}-28=0$$

This equation is in standard form: $ax^{2}+bx+c=0$. Substitute $1$ for $a$, $0$ for $b$, and $-28$ for $c$ in the quadratic formula, $\frac{-b±\sqrt{b^{2}-4ac}}{2a}$.

$$x=\frac{0±\sqrt{0^{2}-4\left(-28\right)}}{2}$$

Square $0$.

$$x=\frac{0±\sqrt{-4\left(-28\right)}}{2}$$

Multiply $-4$ times $-28$.

$$x=\frac{0±\sqrt{112}}{2}$$

Take the square root of $112$.

$$x=\frac{0±4\sqrt{7}}{2}$$

Now solve the equation $x=\frac{0±4\sqrt{7}}{2}$ when $±$ is plus.

$$x=2\sqrt{7}$$

Now solve the equation $x=\frac{0±4\sqrt{7}}{2}$ when $±$ is minus.

$$x=-2\sqrt{7}$$

The equation is now solved.

$$x=2\sqrt{7}$$ $$x=-2\sqrt{7}$$

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Example

Question

Solve for x

Steps by Finding Square Root

Steps Using the Quadratic Formula

Steps by Finding Square Root

Steps Using the Quadratic Formula