$$2x^{2}-3+4$$
$4x$
$$\frac{\mathrm{d}}{\mathrm{d}x}(2x^{2}+1)$$
$$2\times 2x^{2-1}$$
$$4x^{2-1}$$
$$4x^{1}$$
$$4x$$
Show Solution
Hide Solution
$2x^{2}+1$
$$2x^{2}+1$$