How to solve 2x.4=5(x+3)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2x.4=5(x+3) | Equatix

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$$2x.4=5(x+3)$$

$x = -\frac{25}{7} = -3\frac{4}{7} \approx -3.571428571$

Multiply $2$ and $0.4$ to get $0.8$.

$$0.8x=5\left(x+3\right)$$

Use the distributive property to multiply $5$ by $x+3$.

$$0.8x=5x+15$$

Subtract $5x$ from both sides.

$$0.8x-5x=15$$

Combine $0.8x$ and $-5x$ to get $-4.2x$.

$$-4.2x=15$$

Divide both sides by $-4.2$.

$$x=\frac{15}{-4.2}$$

Expand $\frac{15}{-4.2}$ by multiplying both numerator and the denominator by $10$.

$$x=\frac{150}{-42}$$

Reduce the fraction $\frac{150}{-42}$ to lowest terms by extracting and canceling out $6$.

$$x=-\frac{25}{7}$$