How to solve 2y-1/3=5

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2y-1/3=5 | Equatix

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$$2y-1/3=5$$

$y = \frac{8}{3} = 2\frac{2}{3} \approx 2.666666667$

Add $\frac{1}{3}$ to both sides.

$$2y=5+\frac{1}{3}$$

Convert $5$ to fraction $\frac{15}{3}$.

$$2y=\frac{15}{3}+\frac{1}{3}$$

Since $\frac{15}{3}$ and $\frac{1}{3}$ have the same denominator, add them by adding their numerators.

$$2y=\frac{15+1}{3}$$

Add $15$ and $1$ to get $16$.

$$2y=\frac{16}{3}$$

Divide both sides by $2$.

$$y=\frac{\frac{16}{3}}{2}$$

Express $\frac{\frac{16}{3}}{2}$ as a single fraction.

$$y=\frac{16}{3\times 2}$$

Multiply $3$ and $2$ to get $6$.

$$y=\frac{16}{6}$$

Reduce the fraction $\frac{16}{6}$ to lowest terms by extracting and canceling out $2$.

$$y=\frac{8}{3}$$