$$2y+5/3=26/3-y$$
$y = \frac{7}{3} = 2\frac{1}{3} \approx 2.333333333$
$$2y+\frac{5}{3}+y=\frac{26}{3}$$
$$3y+\frac{5}{3}=\frac{26}{3}$$
$$3y=\frac{26}{3}-\frac{5}{3}$$
$$3y=\frac{26-5}{3}$$
$$3y=\frac{21}{3}$$
$$3y=7$$
$$y=\frac{7}{3}$$
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