How to solve 6 3:10 12=?=?=50

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 6 3:10 12=?=?=50 | Equatix

Integers & Absolute Values

Factors & Multiples

Prime Factorization

Basic Equations & Inequalities

Coordinate Plane & Graphing

Linear Equations & Inequalities

Quadratic Equations

Polynomials & Factoring

Functions & Graphs

Systems of Equations

Trigonometric Functions

Trigonometric Identities & Equations

Right Triangle Trigonometry

Unit Circle

Graphing Trigonometric Functions

Limits & Continuity

Derivatives & Applications

Integrals & Applications

Series & Sequences

Multivariable Calculus

Functions & Graphs

Polynomial & Rational Functions

Exponential & Logarithmic Functions

Conic Sections

Sequences & Series

Descriptive Statistics

Eigenvalues & Eigenvectors

Linear Transformations

Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$3 : 10 12 : 12 = ? ? = 50$$

Verify

$\text{false}$

Solution Steps

Multiply both sides of the equation by $12$.

$$\frac{3}{10}\times 12=600$$

Express $\frac{3}{10}\times 12$ as a single fraction.

$$\frac{3\times 12}{10}=600$$

Multiply $3$ and $12$ to get $36$.

$$\frac{36}{10}=600$$

Reduce the fraction $\frac{36}{10}$ to lowest terms by extracting and canceling out $2$.

$$\frac{18}{5}=600$$

Convert $600$ to fraction $\frac{3000}{5}$.

$$\frac{18}{5}=\frac{3000}{5}$$

Compare $\frac{18}{5}$ and $\frac{3000}{5}$.

$$\text{false}$$

Show Solution

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Example

Question

Verify

Solution Steps