$$3 a + 4 b + 5 c , a - 1$$
$\left(a-1\right)\left(3a+4b+5c\right)$
$$\left(a-1\right)\left(3a+4b+5c\right)$$
$$3a^{2}+4ab+5ac-3a-4b-5c$$
Show Solution
Hide Solution
$3a+4b+5c,a-1$
