$$3\bullet5\times10^{-2}+2\cdot3\times10$$
$\frac{1203}{20}=60.15$
$$15\times 10^{-2}+6\times 10$$
$$15\times \frac{1}{100}+6\times 10$$
$$\frac{3}{20}+6\times 10$$
$$\frac{3}{20}+60$$
$$\frac{1203}{20}$$
Show Solution
Hide Solution
$\frac{3 \cdot 401}{2 ^ {2} \cdot 5} = 60\frac{3}{20} = 60.15$