Question

$$3 { x }^{ 2 } -24x+48-5 { x }^{ 2 } +36x-45=8 { x }^{ 2 } -22x+5-40$$

Answer

x=(17+sqrt(669))/10,(17-sqrt(669))/10

Solution


Simplify  \(3{x}^{2}-24x+48-5{x}^{2}+36x-45\)  to  \(-2{x}^{2}+12x+3\).
\[-2{x}^{2}+12x+3=8{x}^{2}-22x+5-40\]
Simplify  \(8{x}^{2}-22x+5-40\)  to  \(8{x}^{2}-22x-35\).
\[-2{x}^{2}+12x+3=8{x}^{2}-22x-35\]
Move all terms to one side.
\[2{x}^{2}-12x-3+8{x}^{2}-22x-35=0\]
Simplify  \(2{x}^{2}-12x-3+8{x}^{2}-22x-35\)  to  \(10{x}^{2}-34x-38\).
\[10{x}^{2}-34x-38=0\]
Use the Quadratic Formula.
\[x=\frac{34+2\sqrt{669}}{20},\frac{34-2\sqrt{669}}{20}\]
Simplify solutions.
\[x=\frac{17+\sqrt{669}}{10},\frac{17-\sqrt{669}}{10}\]

Decimal Form: 4.286503, -0.886503