Question

$$3 { x }^{ 2 } -4x+1=0$$

Answer

x=1/3,1

Solution


Split the second term in \(3{x}^{2}-4x+1\) into two terms.
\[3{x}^{2}-x-3x+1=0\]
Factor out common terms in the first two terms, then in the last two terms.
\[x(3x-1)-(3x-1)=0\]
Factor out the common term \(3x-1\).
\[(3x-1)(x-1)=0\]
Solve for \(x\).
\[x=\frac{1}{3},1\]

Decimal Form: 0.333333, 1