How to solve 3/1=1/2(0+x+-8)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3/1=1/2(0+x+-8) | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$3/1=1/2(0+x+-8)$$

Solve for x

$x=14$

Steps for Solving Linear Equation

Anything divided by one gives itself.

$$3=\frac{1}{2}\left(0+x-8\right)$$

Subtract $8$ from $0$ to get $-8$.

$$3=\frac{1}{2}\left(-8+x\right)$$

Use the distributive property to multiply $\frac{1}{2}$ by $-8+x$.

$$3=\frac{1}{2}\left(-8\right)+\frac{1}{2}x$$

Multiply $\frac{1}{2}$ and $-8$ to get $\frac{-8}{2}$.

$$3=\frac{-8}{2}+\frac{1}{2}x$$

Divide $-8$ by $2$ to get $-4$.

$$3=-4+\frac{1}{2}x$$

Swap sides so that all variable terms are on the left hand side.

$$-4+\frac{1}{2}x=3$$

Add $4$ to both sides.

$$\frac{1}{2}x=3+4$$

Add $3$ and $4$ to get $7$.

$$\frac{1}{2}x=7$$

Multiply both sides by $2$, the reciprocal of $\frac{1}{2}$.

$$x=7\times 2$$

Multiply $7$ and $2$ to get $14$.

$$x=14$$

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Question

Solve for x

Steps for Solving Linear Equation