How to solve 3/10+9/4=

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3/10+9/4= | Equatix

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$$3/10+9/4=$$

$\frac{51}{20}=2.55$

Least common multiple of $10$ and $4$ is $20$. Convert $\frac{3}{10}$ and $\frac{9}{4}$ to fractions with denominator $20$.

$$\frac{6}{20}+\frac{45}{20}$$

Since $\frac{6}{20}$ and $\frac{45}{20}$ have the same denominator, add them by adding their numerators.

$$\frac{6+45}{20}$$

Add $6$ and $45$ to get $51$.

$$\frac{51}{20}$$

$\frac{3 \cdot 17}{2 ^ {2} \cdot 5} = 2\frac{11}{20} = 2.55$