How to solve 3/2+3-7/5=

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3/2+3-7/5= | Equatix

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$$3/2+3-7/5=$$

$\frac{31}{10}=3.1$

Convert $3$ to fraction $\frac{6}{2}$.

$$\frac{3}{2}+\frac{6}{2}-\frac{7}{5}$$

Since $\frac{3}{2}$ and $\frac{6}{2}$ have the same denominator, add them by adding their numerators.

$$\frac{3+6}{2}-\frac{7}{5}$$

Add $3$ and $6$ to get $9$.

$$\frac{9}{2}-\frac{7}{5}$$

Least common multiple of $2$ and $5$ is $10$. Convert $\frac{9}{2}$ and $\frac{7}{5}$ to fractions with denominator $10$.

$$\frac{45}{10}-\frac{14}{10}$$

Since $\frac{45}{10}$ and $\frac{14}{10}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{45-14}{10}$$

Subtract $14$ from $45$ to get $31$.

$$\frac{31}{10}$$

$\frac{31}{2 \cdot 5} = 3\frac{1}{10} = 3.1$